In the diagram, \(A\), \(B\), \(C\) and \(D\) lie on a circle. \(XT\) is the tangent to the circle at \(A\) and the line \(DB\) extended meets the tangent at \(T\). Points \(E\) and \(F\) lie on \(XAT\) and \(DBT\) respectively. \(EF\) is parallel to \(AB\) and point \(E\) is the mid-point of \(AT\). It is given that \(AB\) bisects angle \(CAT\) and \(AD\) bisects angle \(CAX\).
Sign in to view the step-by-step solution
Need help? Join our JC Math tuition classes.
Learn more