2026 MSHS P2 Q2

2026 MSHS P2 Q2

Secondary 4
5 marks

In a sports meet, the height, \(h\) metres, of a javelin thrown by an athlete is modelled by the formula, \(h=-\dfrac3{100}(w^2-36w-76)\), where \(w\) is the horizontal distance travelled by the javelin in metres.

  1. By expressing \(h\) in the form \(A(w-B)^2+C\), where \(A\), \(B\) and \(C\) are constants, find the maximum height reached by the javelin and state the corresponding horizontal distance when this occurs.[3]
  2. Find the horizontal distance covered by the javelin before it hits the ground.[2]

Solution:

Solution locked

Sign in to view the step-by-step solution

Similar questions are unavailable for this question.
Answer:(a) \(h=-\dfrac3{100}(w-18)^2+12\); maximum height 12 m at 18 m. (b) 38 m.

Need help? Join our JC Math tuition classes.

Learn more