2026 MSHS P1 Q10

2026 MSHS P1 Q10

Secondary 4
9 marks
  1. State the amplitude and period of \(-3\sin2x\).[2]
  2. Sketch the graph of \(y=-3\sin2x\) for \(0\le x\le2\pi\).[3]
  3. The equation \(-3\sin2x=k\) has 2 solutions. State a possible value of \(k\).[1]
  4. By drawing a suitable straight line on your sketch, determine the number of solutions of the equation \(-\dfrac1{2\pi}x+1=-\sin2x\).[3]

Solution:

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Answer:(a) Amplitude \(3\), period \(\pi\). (b) See sketch. (c) \(k=3\) or \(-3\). (d) 4 solutions.

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