Show that \(\dfrac{\sin\theta}{\sec\theta-\tan\theta}+\dfrac{\sin\theta}{\sec\theta+\tan\theta}=2\tan\theta\).[3]
Hence solve the equation \(\dfrac{\sin\theta}{\sec\theta-\tan\theta}+\dfrac{\sin\theta}{\sec\theta+\tan\theta}=\cos\theta\) for \(0^\circ\le\theta\le360^\circ\).[5]
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