2026 IGCSE Additional Mathematics May/June 0606/12 Q10

2026 IGCSE Additional Mathematics May/June 0606/12 Q10

8 marks

It is given that a geometric progression has the following terms.

2nd term: \(11x-1\)

3rd term: \(x+5\)

4th term: \(x-1\)

  1. Given that \(x>0\), find the common ratio and first term of the progression.[6]
  2. The sum to infinity of this progression is \(\dfrac k3\) where \(k\) is an integer.
    Find the value of \(k\).[2]

Solution:

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Answer:(a) \(r=\dfrac14,\ a=128\) (b) \(k=512\)

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