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2026 IGCSE Additional Mathematics February/March 0606/22 Q9
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2026 IGCSE Additional Mathematics February/March 0606/22 Q9
12 marks
Show that \(\tan\theta+\cot\theta+2\sec\theta\) can be written as \(\dfrac{1+2\sin\theta}{\sin\theta\cos\theta}\).
[3]
Hence solve the equation \(\tan2x+\cot2x+2\sec2x=0\) for \(-180^\circ\le x\le180^\circ\).
[4]
Solve the equation \(3\sec(x-1)-1=\tan^2(x-1)\) where \(x\) is in radians and \(-1<x<3\).
[5]
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Answer:
(a) Shown. (b) \(x=-75^\circ,-15^\circ,105^\circ,165^\circ\) (c) \(x=-0.231,2.23\)
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