2026 IGCSE Additional Mathematics February/March 0606/12 Q5

2026 IGCSE Additional Mathematics February/March 0606/12 Q5

7 marks

A curve has equation \(y=\dfrac{x^2-8}{3-x}\).

\(P\) and \(Q\) are the stationary points on the curve.

Find \(\dfrac{\mathrm{d}y}{\mathrm{d}x}\) and the exact length of the line \(PQ\).[7]

Solution:

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Answer:\(\dfrac{\mathrm{d}y}{\mathrm{d}x}=\dfrac{-x^2+6x-8}{(3-x)^2}\), \(PQ=2\sqrt5\)

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