2026 HGV P2 Q9

2026 HGV P2 Q9

Secondary 4
10 marks

The velocity, \(v\) m/s, of a particle travelling in a straight line, \(t\) seconds after leaving a fixed point \(O\), is given by \(v=k(t^2-5t)\), where \(k\) is a constant.

The acceleration of the particle is 3 m/s² when \(t=3\).

  1. Find the value of \(k\).[3]
  2. Find the value of \(t\) when the particle first comes to instantaneously at rest.[2]
  3. Show that the total distance covered by the particle during the first 10 seconds is 375 m.[5]

Solution:

Solution locked

Sign in to view the step-by-step solution

Similar questions are unavailable for this question.
Answer:(a) \(k=3\). (b) \(t=5\text{ s}\) after departure. (c) \(375\text{ m}\) (shown).

Need help? Join our JC Math tuition classes.

Learn more