2026 HGV P1 Q9

2026 HGV P1 Q9

Secondary 4
10 marks

A curve is such that \(\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2}=\dfrac{20}{(2x-3)^2}\). Given that the curve passes through \(P(2,5)\) and the normal to the curve at \(P\) is parallel to \(2y=x+6\), find the equation of the curve.[10]

Solution:

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Answer:\(y=-5\ln(2x-3)+8x-11\), on the branch \(x>\dfrac32\) containing \(P\).

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