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2026 HGV P1 Q7
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2026 HGV P1 Q7
Secondary 4
8 marks
Show that \(\dfrac{1-3\sin^2A}{1+\cos2A}=\dfrac12-\tan^2A\).
[3]
Use your answer to part
(a)
to find, for \(0\le A\le2\pi\), the solutions of the equation \(\dfrac{1-3\sin^2A}{1+\cos2A}=\dfrac12\tan A\).
[5]
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Answer:
(a) Identity shown for \(\cos A\ne0\). (b) \(A=0.464,\ 3.61,\ \dfrac{3\pi}4,\ \dfrac{7\pi}4\) radians.
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