2026 HGV P1 Q12

2026 HGV P1 Q12

Secondary 4
7 marks

The equation of a curve is \(y=x^3\tan^2 3x\).

  1. Show that \(\dfrac{\mathrm{d}y}{\mathrm{d}x}=\dfrac{3\pi^2(1-\pi)}{16}\) when \(x=\dfrac\pi4\).[5]
  2. Given that \(y\) is decreasing at a rate of 3 units per second, find the rate of change of \(x\), in terms of \(\pi\), at the instant when \(x=\dfrac\pi4\).[2]

Solution:

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Answer:(a) \(\dfrac{3\pi^2(1-\pi)}{16}\) (shown). (b) \(\dfrac{16}{\pi^2(\pi-1)}\) units per second, increasing.

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