2026 DSS P2 Q6

Secondary 4

10 marks

The table of values for \(y=\dfrac5x+2x-4\) is given below. Values are given to one decimal place where appropriate.
\(x\) 0.5 1 1.5 2 2.5 3 4 5 6
\(y\) 7 3 \(p\) 2.5 3 3.7 5.3 7 8.8
Find the value of \(p\).[1]
On the grid below, draw the graph of \(y=\dfrac5x+2x-4\) for \(0.5\leq x\leq6\).[3]
The equation \(x^2-9x+5=0\) can be solved by finding the points of intersection of the straight line \(y=ax+b\) and the curve \(y=\dfrac5x+2x-4\).
1. Find the values of \(a\) and \(b\).[3]
2. On the same grid, draw the straight line \(y=ax+b\).[2]
3. Hence, from the graph, state the solution of \(x^2-9x+5=0\) for \(0.5\leq x\leq6\).[1]

\(x\)	0.5	1	1.5	2	2.5	3	4	5	6
\(y\)	7	3	\(p\)	2.5	3	3.7	5.3	7	8.8

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Answer:(a) 2.3. (b) See curve. (c)(i) a=1,b=5 (ii) y=x+5 (iii) x≈0.6.

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