2026 DSS P1 Q9

2026 DSS P1 Q9

Secondary 4
8 marks
  1. Find the amplitude and period of \(4-3\sin2x\).[2]
  2. Sketch the graph of \(y=4-3\sin2x\) for \(0\le x\le\pi\) radians.[3]
  3. By drawing a suitable straight line in your sketch, explain why the equation \(3\pi\sin2x=-4x\) has no solution for \(x>\dfrac{3\pi}{4}\).[3]

Solution:

Solution locked

Sign in to view the step-by-step solution

Similar questions are unavailable for this question.
Answer:(a) Amplitude 3, period \(\pi\). (b) Sketch shown. (c) \(y=4+\dfrac{4x}{\pi}>7\) for \(x>\dfrac{3\pi}4\), above the curve’s maximum.

Need help? Join our JC Math tuition classes.

Learn more