2026 DSS P1 Q10

2026 DSS P1 Q10

Secondary 4
7 marks
  1. Find, in ascending powers of \(x\), the first four terms in the expansion of \((2-kx)^8\), where \(k\) is a positive constant. Simplify the coefficients in your expression.[3]
  2. Given that the coefficient of \(x^2\) in the expansion of \(\left(5+\dfrac3{kx}\right)(2-kx)^8\) is 896, find the value of \(k\).[4]

Solution:

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Answer:(a) \(256-1024kx+1792k^2x^2-1792k^3x^3\). (b) \(k=\dfrac12\).

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