2026 CVSS P2 Q2

2026 CVSS P2 Q2

Secondary 4
7 marks

A shop sells \(x\) cups of bubble tea per day. Its daily profit, \(P(x)\) is calculated by subtracting its cost \(C(x)\) from its revenue \(R(x)\). It is given that its cost, \(C(x)=\$(140+0.5x)\) and its revenue, \(R(x)=\$(4.5x-0.01x^2)\).

  1. Express its profit, \(P(x)\) in the form \(A-B(x+c)^2\), where \(A,B\) and \(C\) are constants.[3]
  2. State the maximum daily profit and the corresponding number of cups of bubble tea that should be sold on that day.[2]
  3. Find the total lost incurred if the shop closes for 5 days due to manpower shortage.[2]

Solution:

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Answer:(a) \(260-0.01(x-200)^2\). (b) \(\$260\), 200 cups. (c) \(\$700\).

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