By considering the general term of \(\left(6x-\dfrac ax\right)^5\), where \(a\) is a constant, explain why all the terms in the expansion are dependent on \(x\).[3]
Given that the coefficient of \(x\) is 18 times larger than the coefficient of \(x^{-3}\), find the possible values of \(a\).[5]
Solution:
Solution locked
Sign in to view the step-by-step solution
Similar questions are unavailable for this question.
Answer:(a) No integer \(r\) gives exponent zero. (b) \(a=0,\pm2\) for the coefficient equation; \(\pm2\) if non-zero coefficients are intended.