2026 CVSS P1 Q3

2026 CVSS P1 Q3

Secondary 4
12 marks
  1. Find, in exact value, the equation of the tangent of the curve \(y=\ln\left(\dfrac{12x}{(2x-7)^2}\right)\) at the point \(x=4\).[6]
  2. The tangent intersects the line \(y=-\dfrac74x+17\) at \(Q\). Show that the \(x\)-coordinate of \(Q\) is \(-1+\ln4\sqrt3\).[3]
  3. Two points are given by \(P(-1,-10)\) and \(R(5,4)\). Calculate the area of triangle \(QPR\) to 1 decimal place.[3]

Solution:

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Answer:(a) \(y=-15x/4+15+\ln48\). (b) Shown. (c) \(62.5\) units\(^2\).

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