Back
2026 CSS P2 Q8
Save PDF
2026 CSS P2 Q8
Secondary 4
12 marks
The position vector of point \(X\) is \(\begin{pmatrix}8 \\ -4\end{pmatrix}\).
The position vector of point \(Y\) is \(\begin{pmatrix}6 \\ 4\end{pmatrix}\).
Find the vector that represents the translation from \(X\) to \(Y\).
[1]
Find the magnitude of \(\overrightarrow{XY}\).
[2]
\(Z\) has coordinates \((-1,k)\) and lies on the line \(XY\) produced.
Find the position vector of point \(Z\).
[2]
In the diagram, \(\overrightarrow{AB}=4\mathbf a\), \(\overrightarrow{AD}=8\mathbf b\) and \(\overrightarrow{EF}=2(\mathbf a-\mathbf b)\).
\(E\) is the point on \(BD\) such that \(BE:BD=3:4\).
\(F\) is the midpoint of \(BC\).
Express \(\overrightarrow{BE}\) in terms of \(\mathbf a\) and \(\mathbf b\), as simply as possible.
[2]
Express \(\overrightarrow{BC}\) in terms of \(\mathbf a\) and \(\mathbf b\), as simply as possible.
[2]
What type of quadrilateral is \(ABCD\)? Justify your answer using vectors.
[3]
Solution:
Solution locked
Sign in to view the step-by-step solution
Sign in to view
E Math Tuition
Similar Questions
Similar questions are unavailable for this question.
Answer:
(a)(i) \(\begin{pmatrix}-2 \\ 8\end{pmatrix}\) (ii) \(2\sqrt{17}\approx8.25\) units (iii) \(\begin{pmatrix}-1 \\ 32\end{pmatrix}\) (b)(i) \(6\mathbf b-3\mathbf a\) (ii) \(8\mathbf b-2\mathbf a\) (iii) Trapezium, since \(\overrightarrow{AB}=2\overrightarrow{DC}\).
Need help?
Join our JC Math tuition classes.
Learn more