2026 CCHMS P2 Q7

2026 CCHMS P2 Q7

Secondary 4
10 marks

In the diagram, \(OABC\) is a quadrilateral where the diagonals \(OB\) and \(AC\) intersect at \(X\).

\(\overrightarrow{OA}=\mathbf a\), \(\overrightarrow{OC}=\mathbf b\) and \(\overrightarrow{OB}=2\mathbf a+\mathbf b\). The lines \(BA\) and \(CO\) are produced to meet at \(P\).

  1. Find \(\overrightarrow{CB}\), giving your answer in terms of \(\mathbf a\) and/or \(\mathbf b\).
    Hence, explain why \(ABCO\) is a trapezium.[3]
  2. Giving your answers in terms of \(\mathbf a\) and/or \(\mathbf b\), find
    1. \(\overrightarrow{OX}\),[1]
    2. \(\overrightarrow{AB}\).[1]
  3. Find the ratio of area of triangle \(OAX\) : area of triangle \(OAC\).[1]
  4. Using vector method, find \(\overrightarrow{OP}\) and show that \(O\) is the midpoint of \(PC\).[4]

Solution:

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Answer:(a) \(2\mathbf a\), so \(CB\parallel OA\). (b)(i) \(\dfrac23\mathbf a+\dfrac13\mathbf b\) (ii) \(\mathbf a+\mathbf b\). (c) \(1:3\). (d) \(\overrightarrow{OP}=-\mathbf b\); \(O\) is the midpoint of \(PC\).

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