Given that \(x:y:a=1:2:3\), find the value of \(y\).[3]
Solve the equation \(x^2+10x-7=0\) by completing the square.
Give your solutions correct to 1 decimal place.[4]
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Answer:(a)(i) \(x=\dfrac{a^2}{6-ay}\) (ii) \(y=1\) for positive ratio quantities; \(y=-4\) also satisfies unrestricted proportionality. (b) \(-10.7\) or \(0.7\).