2026 CCHMS P1 Q16

2026 CCHMS P1 Q16

Secondary 4
5 marks
  1. In the diagram, \(AB=10\) cm. Given that \(\angle BAC=70^\circ\) and \(AC=8\) cm, construct the triangle \(ABC\) in the space given below.[2]
  2. On the same diagram, construct the
    1. perpendicular bisector of \(BC\),[1]
    2. angle bisector of \(\angle ABC\).[1]
  3. Mark and label on the diagram, the point \(P\) such that \(P\) is equidistant from point \(B\) and point \(C\) and is nearer to \(AB\) than \(BC\).[1]

Solution:

Solution locked

Sign in to view the step-by-step solution

Similar questions are unavailable for this question.
Answer:(a), (b) See construction. (c) Any point on the perpendicular bisector of \(BC\) nearer to \(AB\) than \(BC\), such as the marked \(P\).

Need help? Join our JC Math tuition classes.

Learn more