2026 AHS P2 Q8

Water is leaking from a container at a constant rate of \(0.4\text{ cm}^3/\text{s}\). When the depth of the water in the container is \(x\text{ cm}\), the volume, \(V\text{ cm}^3\), of water in the container is given by

\[V=\dfrac{1-2x}{x-3}+5\qquad(x\ne3)\]

Find the rate of change of the depth of water when \(x=4\text{ cm}\).[5]