The cubic polynomial \(\mathrm{f}(x)\) is such that the roots of \(\mathrm{f}(x)=0\) are \(-2\), \(1\) and \(k\). It is given that \(\mathrm{f}(x)\) has a remainder of \(-24\) when divided by \(x\), and a remainder of \(-18\) when divided by \((x+1)\).
Sign in to view the step-by-step solution
Need help? Join our JC Math tuition classes.
Learn more