2026 AHS P2 Q10

2026 AHS P2 Q10

Secondary 4
9 marks

A ball is rolled down a skateboard ramp. Its height \(h\text{ m}\), above the ground at \(t\) seconds after being released is given by the formula \(h=0.1t^2-t+3\).

  1. State the height of the ramp from which the ball is first released.[1]
  2. Express \(h\) in the form of \(a(t+b)^2+c\) where \(a\), \(b\) and \(c\) are constants to be determined.[3]
  3. State the minimum height attained by the ball and the time at which this occurs.[2]
  4. Find the times at which the ball is \(2.5\text{ m}\) above the ground.[3]

Solution:

Solution locked

Sign in to view the step-by-step solution

Similar questions are unavailable for this question.
Answer:(a) \(3\text{ m}\). (b) \(0.1(t-5)^2+0.5\). (c) \(0.5\text{ m}\), at \(5\text{ s}\). (d) \(0.528\text{ s}\), \(9.47\text{ s}\).

Need help? Join our JC Math tuition classes.

Learn more