2025 YIJC Promo Q11 [Modified]

2025 YIJC Promo Q11 [Modified]

Junior College 1
10 marks

The function \(\mathrm{f}\) is defined by

\[\mathrm{f}: x \mapsto \frac{1}{x^2 + 1}, \quad x \in \mathbb{R}, \: x \le 0.\]

  1. Sketch the graph of \(\mathrm{f}\) and explain why the function \(\mathrm{f}^{-1}\) exists.[2]
  2. Find \(\mathrm{f}^{-1}(x)\) and state the domain of \(\mathrm{f}^{-1}\).[3]

The function \(\mathrm{g}\) is defined by

\[\mathrm{g}: x \mapsto \mathrm{e}^{-x} - 1, \quad x \in \mathbb{R}, \: x \le 1.\]

  1. Find the value of \(a\) such that \(\mathrm{g}^{-1}(a) = 2\).[1]
  2. Explain why the composite function \(\mathrm{gf}\) exists.[1]
  3. Find \(\mathrm{gf}(x)\) and state the domain of \(\mathrm{gf}\).[2]
  4. Find the exact range of \(\mathrm{gf}\).

    [1]

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Answer:\(\mathrm{f}^{-1}(x)=-\sqrt{\dfrac1x-1}\), \(0<x\le1\); \(a=e^{-2}-1\); \(\mathrm{gf}(x)=e^{-1/(x^2+1)}-1\), \(x\le0\)

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