2025 YCKSS PRELIMS P2 Q4

2025 YCKSS PRELIMS P2 Q4

Secondary 4
12 marks

The function is \(y=\dfrac{x}{4}(8-6x+x^2)\).

  1. Complete the table, giving the missing value correct to 2 decimal places.[1]
    \(x\)\(-1\)\(0\)\(0.5\)\(1\)\(1.5\)\(2\)\(2.5\)\(3\)\(4\)\(5\)
    \(y\)\(-3.75\)\(0\)\(0.75\)\(0.47\)\(0\)\(-0.47\)\(-0.75\)\(0\)\(3.75\)
  2. Draw the graph for \(-1\leq x\leq5\).[3]
  3. Use the graph to solve \(x^3-6x^2+8x=12\) for \(-1\leq x\leq5\).[2]
    1. Line \(L\) has gradient \(-0.5\) and passes through \((3,1)\). Draw \(L\) on the same axes for \(-1\leq x\leq5\).[2]
    2. Write the x-coordinate where L intersects the curve.[1]
    3. This x-value solves \(x^3+Ax^2+Bx+C=0\). Find \(A,B,C\).[3]

Solution:

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Answer:(a) \(0.66\) (c) \(x\approx4.9\) (d)(i) \(y=-\dfrac12x+\dfrac52\) (ii) \(x\approx4.2\) (iii) \(A=-6,\ B=10,\ C=-10\)

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