2025 VJC Promo Q9

2025 VJC Promo Q9

Junior College 1
10 marks

A curve \(C\) has equation \(y=\dfrac{x^2-4x+1}{x+1}\), \(x \ne -1\).

  1. Prove, using an algebraic method, that \(y=\dfrac{x^2-4x+1}{x+1}\) cannot lie between two certain values, to be determined in exact form.[3]
  2. Sketch \(C\), stating the equations of any asymptotes, and the coordinates of any turning points and any axial intercepts.[4]
  3. The curve \(C\) undergoes, in succession, the following transformations.
    1. A translation of 1 unit in the positive \(x\)-direction,
    2. A stretch parallel to the \(x\)-axis, factor \(3\), \(y\)-axis invariant,

    3. A reflection in the \(y\)-axis.
    Find the equation of the new curve in the form \(y=\mathrm{f}(x)\).[3]

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Answer:Excluded range \((-6-2\sqrt6,-6+2\sqrt6)\); new curve \(y=-\dfrac{x}{3}-6-\dfrac{18}{x}\)

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