A curve \(C\) has equation \(y=\dfrac{x^2-4x+1}{x+1}\), \(x \ne -1\).
Prove, using an algebraic method, that \(y=\dfrac{x^2-4x+1}{x+1}\) cannot lie between two certain values, to be determined in exact form.[3]
Sketch \(C\), stating the equations of any asymptotes, and the coordinates of any turning points and any axial intercepts.[4]
The curve \(C\) undergoes, in succession, the following transformations.
A translation of 1 unit in the positive \(x\)-direction,
A stretch parallel to the \(x\)-axis, factor \(3\), \(y\)-axis invariant,
A reflection in the \(y\)-axis.
Find the equation of the new curve in the form \(y=\mathrm{f}(x)\).[3]