Two events \(A\) and \(B\) are such that \(\mathrm{P}(A) = p\) and \(\mathrm{P}(B) = \frac{5}{4}p\). It is given that \(\mathrm{P}(A \cup B) = \mathrm{P}(A|B) = 0.6\).
The events \(C\) and \(D\) are such that \(\mathrm{P}(C) = 0.55\), \(\mathrm{P}(D) = 0.6\) and \(\mathrm{P}(A \cap C) = \mathrm{P}(A \cap D) = \mathrm{P}(C \cap D) = q\).
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