Referred to the origin \(O\), points \(A\) and \(B\) have position vectors \(\mathbf{a}\) and \(\mathbf{b}\) respectively. Point \(C\) lies on \(OA\), such that \(OC:CA=2:1\). Point \(D\) lies on \(OB\), such that \(OD:DB=\lambda:\mu\). It is given that the area of triangle \(ABD\) is half the area of triangle \(ABC\).
It is further given that the angle \(AOB\) is \(\frac{\pi}{4}\) and \(O\) lies on the perpendicular bisector of the line segment \(AB\).
Video solution locked
Sign in to view the step-by-step solution
Need help? Join our JC Math tuition classes.
Learn more