2025 VJC P1 Q3

2025 VJC P1 Q3

10 marks

Referred to the origin \(O\), points \(A\) and \(B\) have position vectors \(\mathbf{a}\) and \(\mathbf{b}\) respectively. Point \(C\) lies on \(OA\), such that \(OC:CA=2:1\). Point \(D\) lies on \(OB\), such that \(OD:DB=\lambda:\mu\). It is given that the area of triangle \(ABD\) is half the area of triangle \(ABC\).

  1. Show the area of triangle \(ABD\) is given by \(\frac{\mu}{2(\lambda+\mu)} |\mathbf{a} \times \mathbf{b}|\). Hence find the ratio \(\lambda:\mu\).[4]
  2. The point \(E\) has position vector \(\frac{1}{4}\mathbf{a}+\frac{5}{8}\mathbf{b}\). Show that \(A\), \(E\) and \(D\) are collinear.[3]

It is further given that the angle \(AOB\) is \(\frac{\pi}{4}\) and \(O\) lies on the perpendicular bisector of the line segment \(AB\).

  1. Find the length of projection of \(\mathbf{a}\) on \(\mathbf{b}\), giving your answer in terms of \(|\mathbf{b}|\). Hence find the position vector of the point \(F\), the foot of perpendicular from \(A\) to \(OB\).[3]

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Answer:(a) \(\lambda:\mu=5:1\); (b) \(A,E,D\) are collinear; (c) \(\overrightarrow{OF}=\frac{\mathbf b}{\sqrt2}\)

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