2025 VJC P1 Q1

2025 VJC P1 Q1

Using an algebraic method, solve the inequality \(\frac{4x-3}{4x^2+3x-1} \leq 1\)

Hence, find the set of values of \(x\) that satisfy \(\frac{4 \ln x - 3}{4(\ln x)^2 + 3 \ln x - 1} \leq 1\)

Solution:

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Answer:First inequality: \(x<-1\) or \(x>\frac{1}{4}\). Logarithmic inequality: \(0<x<\mathrm e^{-1}\) or \(x>\mathrm e^{\frac{1}{4}}\).

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