2025 TMJC P2 Q3

2025 TMJC P2 Q3

6 marks

The function \(\mathrm{f}\) is defined by

\[\mathrm{f}(x) = \begin{cases} x+4 & \text{for}\hspace{0.5em} -4 \le x < -1, \\ x^2+2 & \text{for}\hspace{0.5em} -1 \le x < 2. \end{cases}\]

It is given that \(\mathrm{f}(x) = \mathrm{f}(x+6)\) for all real values of \(x\).

  1. Sketch the graph of \(y = \mathrm{f}(x)\) for \(-6 \le x < 6\).[3]
  2. Hence sketch the graph of \(y = 2\mathrm{f}(x-1)\) for \(-6 \le x < 6\).[3]

Solution:

Solution locked

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Answer:(a) Period-6 sketch shown on \(-6\le x<6\). (b) Right translation 1 and vertical stretch factor 2; transformed sketch shown, with lower jump endpoints included and upper endpoints excluded.

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