2025 TMJC P2 Q10

2025 TMJC P2 Q10

10 marks

Wardrobe \(A\) contains \(4\) distinct blouses, labelled \(T_1, T_2, T_3\) and \(T_4\). Wardrobe \(B\) contains \(3\) distinct pairs of pants, labelled \(P_1, P_2\) and \(P_3\). The following table shows the formality (formal or casual) of all the clothing.

WardrobeClothingFormalCasual
\(A\)Blouse\(T_1, T_2\)\(T_3, T_4\)
\(B\)Pants\(P_1, P_2\)\(P_3\)

Nancy selects an outfit at random, by first choosing one blouse from Wardrobe \(A\), followed by choosing one pair of pants from Wardrobe \(B\).

\(X\) denotes the score of a randomly chosen outfit.

• If the blouse and pants have the same formality, then the score of the outfit is the sum of their respective indices. For example, the score of an outfit comprising \(T_4\) and \(P_3\) is \(7\).
• If the blouse and pants have different formality, then the score of the outfit is the product of their respective indices. For example, the score of an outfit comprising \(T_2\) and \(P_3\) is \(6\).

  1. Show that \(\mathrm{P}(X=4) = \frac{1}{6}\).[1]
  2. Find the probability distribution of \(X\).[3]
  3. Show that \(\mathrm{E}(X) = \frac{55}{12}\) and find \(\mathrm{Var}(X)\).[3]
  4. Nancy selects three outfits in succession without replacement. Find the probability that there are exactly two outfits that comprise both a formal blouse and a pair of formal pants.[3]

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:(a) \(\dfrac16\) (b) For \(x=2,3,4,6,7,8\), \(\mathrm P(X=x)=\dfrac1{12},\dfrac4{12},\dfrac2{12},\dfrac3{12},\dfrac1{12},\dfrac1{12}\) respectively (c) \(\mathrm E(X)=\dfrac{55}{12}\), \(\operatorname{Var}(X)=\dfrac{491}{144}\) (d) \(\dfrac16\)

Need help? Join our JC Math tuition classes.

Learn more