The function \(\mathrm{f}\) is such that\[\mathrm{f} : x \mapsto \frac{1}{2} \sqrt{36 - (x - 3)^2} \text{ for}\hspace{0.5em} x \in \mathbb{R}, \, k \leq x < 9,\]where \(k\) is a real constant.
For the rest of the question, take the value of \(k\) as the value found in part (a).
The function \(\mathrm{g}\) is such that\[\mathrm{g} : x \mapsto |4x - 1|(2x - 5) \text{ for}\hspace{0.5em} x \in \mathbb{R}, \, x > 0.\]
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