[The arc length \(L\) of a sector of radius \(a\) and angle \(\theta\) is given by \(L=a\theta\);
The volume \(V\) of a cone of base radius \(r\) and height \(h\) is given by \(V=\frac{1}{3}\pi r^2h\)]

A metal sheet is shaped as a circular sector with angle \(\theta\) and fixed radius \(a\), as shown in Figure \(1\). This sector is then formed into a right circular cone with slant height \(a\) by joining the two radii \(OA\) and \(OB\) together as shown in Figure \(2\).

Two identical cones, as described in part (c), are joined together tip-to-tip to form a new object, as shown in Figure \(3\). The upper cone is initially filled with water, which leaks out into the lower cone at a rate of \(\frac{\pi}{15}\) cm\(^3\) s\(^{-1}\). At time \(t\) seconds, the height of the water in the upper cone is \(y\).
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