2025 TJC P1 Q6

2025 TJC P1 Q6

8 marks

The points \(A\) and \(B\) lie on a circle with center \(O\) and radius \(\lambda\) unit. With reference to the origin \(O\), points \(A\) and \(B\) have position vectors \(\mathbf{a}\) and \(\mathbf{b}\) respectively. The point \(X\) on the line segment \(AB\) is such that \(AX:XB = 1:3\) and the point \(Y\) is the foot of perpendicular of \(X\) on \(OB\).

  1. Find the position vector of \(X\).[1]

It is given that the acute angle \(AOB\) is \(\frac{\pi}{6}\).

  1. Find \(\mathbf{a} \cdot \mathbf{b}\) in terms of \(\lambda\).[1]
  2. Show that the position vector of \(Y\) is \(\frac{2 + 3\sqrt{3}}{8} \mathbf{b}\).[2]
  3. Hence find the exact area of \(\Delta OXY\) in term of \(\lambda\).[4]

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Answer:(a) \(\overrightarrow{OX} = \dfrac{3\mathbf{a} + \mathbf{b}}{4}\) (b) \(\dfrac{\sqrt{3}}{2}\lambda^2\) (d) \(\dfrac{3(2 + 3\sqrt{3})}{128}\lambda^2\) units\(^2\)

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