2025 TJC P1 Q5

2025 TJC P1 Q5

7 marks

Without using a calculator, solve the inequality \(\frac{2x - 25}{x^2 - 2x - 3} \leq 2\).[4]
Hence solve the inequality \(\frac{2|x + 1| - 25}{(x + 1)^2 - 2|x + 1| - 3} \leq 2\).[3]

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Answer:(a) \(x < -1\) or \(x > 3\) (b) \(x > 2\) or \(x < -4\)

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