2025 TJC P1 Q5

2025 TJC P1 Q5

7 marks
  1. Without using a calculator, solve the inequality \(\frac{2x - 25}{x^2 - 2x - 3} \leq 2\).[4]
  2. Hence solve the inequality \(\frac{2|x + 1| - 25}{(x + 1)^2 - 2|x + 1| - 3} \leq 2\).[3]

Video Solution:

Video Solution

Video solution locked

Solution:

Solution locked

Sign in to view the step-by-step solution

Finding similar questions...
Answer:(a) \(x < -1\) or \(x > 3\) (b) \(x > 2\) or \(x < -4\)

Need help? Join our JC Math tuition classes.

Learn more