In the diagram, the point \(P\) lies on the circle and \(TP\) is a tangent to the circle. \(TS\) is a straight line intersecting the circle at \(Q\) and \(S\). Given that point \(R\) lies on \(TS\) and \(TP = TR\), prove that the line \(PR\) bisects the angle \(SPQ\).[4]
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