Points \(E\) and \(F\) lie on a circle with centre \(O\). \(D,O,F\) are collinear and \(DE\) is tangent at \(E\). Also \(\angle FEO=x^\circ\) and \(\angle EDO=y^\circ\).
Show that \(y=90-2x\), stating all reasons clearly.[3]
Given that \(y+x=60\), find \(\angle EOD\).[2]
A circle passes through \(A,B,C,D,E\). \(A,F,D\) and \(B,F,E\) are straight lines, \(EA\parallel DB\), \(\angle ABE=49^\circ\), and \(\angle ADB=27^\circ\).
Find \(\angle AFE\), giving a reason for each step.[2]
Find \(\angle BCD\), giving a reason for each step.[3]
Solution:
Solution locked
Sign in to view the step-by-step solution
Similar questions are unavailable for this question.
Answer:(a)(i) shown (ii) \(60^\circ\) (b)(i) \(126^\circ\) (ii) \(103^\circ\)