2025 SST PRELIMS P2 Q4

The function is \(y=\dfrac{x^2}{7}+\dfrac2x-5\).

1. Complete the table, giving values to one decimal place where appropriate.[1]

   \(x\)	\(0.2\)	\(0.5\)	\(1\)	\(2\)	\(3\)	\(4\)	\(5\)	\(6\)
   \(y\)		\(-1.0\)	\(-2.9\)	\(-3.4\)	\(-3.0\)	\(-2.2\)	\(-1.0\)	\(0.5\)

2. On a grid, draw \(y=\dfrac{x^2}{7}+\dfrac2x-5\) for \(0<x\leq6\).[2]
3. Use your graph to write an inequality in \(x\) describing where \(y<-2\).[1]
4. 1. On the same grid, draw \(2y+4x=9\) for \(0<x\leq6\).[2]
   2. Write down the x-coordinates of the points where the line intersects the curve.[1]
   3. These x-values solve \(2x^3+Ax^2-Bx+28=0\). Find \(A\) and \(B\).[4]