2025 SJI PRELIMS P1 Q11

2025 SJI PRELIMS P1 Q11

Secondary 4
4 marks

The sequence begins \(T_1=1^2+1^2=2\), \(T_2=5^2+2^2=29\), \(T_3=9^2+3^2=90\), \(T_4=13^2+4^2=185\).

  1. Evaluate \(T_5\).[1]
  2. Find \(T_n\) in the form \(an^2+bn+c\), where \(a,b,c\) are integers.[3]

Solution:

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Answer:(a) \(314\) (b) \(17n^2-24n+9\)

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