2025 SCGS PRELIMS P1 Q8

2025 SCGS PRELIMS P1 Q8

Secondary 4
9 marks

The highest point on a circle \(C_1\) is \((2, 8)\). The equation of the tangent, \(T\), to \(C_1\) at the point \((6, 6)\) is \(3y + 4x = 42\).

  1. Find the equation of \(C_1\).[6]

A second circle, \(C_2\), is the reflection of \(C_1\) in the line \(T\).

  1. Find the equation of \(C_2\).[3]

Solution:

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Answer:(a) \(C_1:(x-2)^2+(y-3)^2=25\) (b) \(C_2:(x-10)^2+(y-9)^2=25\)

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