<p>The equation of a curve is \(y = (m+1)x^2 - 8x + 3m\), where&nbsp;\(m\) is a constant.</p>
<ol class="abc-list"><li><div class="list-item-content"><span class="list-item-text">In the case where&nbsp;\(m = 1\), show that the line \(y = 1 - 4x\) is a tangent to the curve. Find the coordinates of the point of contact.</span><span class="inline-marks">[3]</span></div></li><li><div class="list-item-content"><span class="list-item-text">Find the range of values of \(m\) for which the curve is above the line \(y = 5\).</span><span class="inline-marks">[5]</span></div></li></ol>

The equation of a curve is \(y = (m+1)x^2 - 8x + 3m\), where \(m\) is a constant.

In the case where \(m = 1\), show that the line \(y = 1 - 4x\) is a tangent to the curve. Find the coordinates of the point of contact.

Find the range of values of \(m\) for which the curve is above the line \(y = 5\).

2025 SCGS PRELIMS P1 Q5

2025 SCGS PRELIMS P1 Q5