An arrow is shot towards a target in an archery competition.
Its height, \(h\) m, above the ground at time \(t\) seconds after being shot is given by the formula \(h = 1.69 + 0.9t - 0.25t^2\).
State the height above the ground from which the arrow is shot.[1]
Express \(h\) in the form \(a + b(t + c)^2\), where \(a\), \(b\) and \(c\) are constants.[3]
Hence state the maximum height attained by the arrow and the time at which this occurs.[2]
The arrow missed the target and hit the ground. Explain why the time taken for the arrow to hit the ground is not twice the time found in part (iii).[1]
Find the length of time for which the arrow is at least \(2.19\) m above the ground.[3]