The diagram above shows the triangle \(ABC\). The points \(P\), \(Q\) and \(R\) are the midpoints of the line segments \(AB\), \(BC\) and \(AC\) respectively.
Let \(\overrightarrow{OA} = \mathbf{a}\), \(\overrightarrow{OB} = \mathbf{b}\) and \(\overrightarrow{OC} = \mathbf{c}\).
Find \(\overrightarrow{BR}\) in terms of \(\mathbf{a}\), \(\mathbf{b}\) and \(\mathbf{c}\).
[2]Point \(G\) is the point where \(BR\) and \(AQ\) intersect.
By finding the vector line equations of lines \(BR\) and \(AQ\) in terms of \(\mathbf{a}\), \(\mathbf{b}\) and \(\mathbf{c}\) and their respective parameters. Show that \(\overrightarrow{OG} = \frac{1}{3}(\mathbf{a} + \mathbf{b} + \mathbf{c})\).
[5]A point \(X\) is such that \(GX\) is perpendicular to the plane \(ABC\). The coordinates of \(A\), \(B\) and \(C\) are \((1, 3, 1)\), \((3, 7, -5)\) and \((2, 2, 1)\) respectively.
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