2025 PHS PRELIMS P1 Q22

2025 PHS PRELIMS P1 Q22

Secondary 4
5 marks

Box X contains balls numbered 1, 2, 3 and 4. Box Y contains balls numbered 1, 3, 5 and 6. May draws one ball at random from each box and adds the numbers.

  1. Complete the possibility diagram.[2]
    \(X + Y\)\(1\)\(3\)\(5\)\(6\)
    \(1\)\(2\)\(7\)
    \(2\)\(5\)
    \(3\)\(8\)
    \(4\)\(7\)\(10\)
  2. Find the probability that the sum is 6.[1]
  3. Box Z contains balls numbered 10, 20, 30 and 40. Albert draws one ball from each of X, Y and Z. Find the probability that their sum is more than 30 but less than 36.[2]

Solution:

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Answer:(a) completed diagram (b) \(\frac18\) (c) \(\frac3{32}\)

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