The function \(\mathrm{f}\) is defined by \(\mathrm{f}(x)=2x^2-6x+9\).
Express \(2x^2-6x+9\) in the form \(p(x-q)^2+r\), where \(p\), \(q\) and \(r\) are constants.[2]
Explain why the lowest point on the curve \(y=\mathrm{f}(x)\) has coordinates \((1.5,4.5)\).[2]
State the range of values of \(k\) for which \(\mathrm{f}(x)=k\) has no solutions.[1]