2025 NYJC P2 Q1
2025 NYJC P2 Q1
6 marks
- Find the set of values of \(x\) for which \(3|x - 3| \leq |1 - 2x|\).[2]
- Without using a calculator, solve \(\frac{x + 18}{x^2 + 5x - 14} \geq -1\).[4]
Solution:
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Answer:(a) \(\{x\in\mathbb R:2\le x\le8\}\). (b) \(x<-7\) or \(-3-\sqrt5\le x\le-3+\sqrt5\) or \(x>2\).
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