$y=(x-h)^2+k$. Explain why $y$ has its minimum value when $x=h$.[1] The roots of \((x-h)^

Question

$y=(x-h)^2+k$. Explain why $y$ has its minimum value when $x=h$.[1] The roots of $(x-h)^2+k=0$ are $-2$ and 4. Explain why $h=1$.[1] Find the minimum value of (y).[1] Sketch the graph of (y), clearly indicating its (x)-intercepts and minimum point.[2]

Accepted Answer

(a) minimum at $x=h$ (b) $h=1$ (c) $-9$ (d) vertex $(1,-9)$, roots $(-2,0),(4,0)$

2025 NASS PRELIMS P1 Q18

2025 NASS PRELIMS P1 Q18

Solution:

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