2025 MSHS PRELIMS P2 Q4

2025 MSHS PRELIMS P2 Q4

Secondary 4
7 marks

In the diagram, \(AB\) is the diameter of the circle with centre \(O\). \(DE\) and \(BF\) are tangents to the circle at \(C\) and \(B\) respectively. \(DCE\) and \(BEF\) are straight lines.

  1. Prove that triangle \(ABC\) and triangle \(AFB\) are similar.[3]
  2. Show that \(EC=EF\).[4]

Solution:

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Answer:\(\text{(a)}\hspace{0.5em}\triangle ABC\sim\triangle AFB\text{ [AA similarity]}\quad\text{(b)}\hspace{0.5em}EC=EF\).

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