2025 MI PU1 Promo Q2

2025 MI PU1 Promo Q2

Junior College 1
4 marks

The diagram shows the graph of \( y=\mathrm{f}(x) \). The curve has one vertical asymptote at \( x=-2 \) and one horizontal asymptote at \( y=2 \). The graph passes through the points \( (-3,0) \), \( (0,3) \) and has one turning point at \( (3,1) \).

Sketch the graph of \( y=\frac{1}{\mathrm{f}(x)} \), labelling the equations of any asymptotes and coordinates of the axial intercepts and turning point where applicable.[4]

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Answer:Asymptotes \(x=-3\), \(y=\dfrac12\); labelled points \((-2,0)\), \((0,\dfrac13)\), \((3,1)\)

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